y^2-12y+28=0

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Solution for y^2-12y+28=0 equation:


Simplifying
y2 + -12y + 28 = 0

Reorder the terms:
28 + -12y + y2 = 0

Solving
28 + -12y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + -12y + -28 + y2 = 0 + -28

Reorder the terms:
28 + -28 + -12y + y2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + -12y + y2 = 0 + -28
-12y + y2 = 0 + -28

Combine like terms: 0 + -28 = -28
-12y + y2 = -28

The y term is -12y.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12y + 36 + y2 = -28 + 36

Reorder the terms:
36 + -12y + y2 = -28 + 36

Combine like terms: -28 + 36 = 8
36 + -12y + y2 = 8

Factor a perfect square on the left side:
(y + -6)(y + -6) = 8

Calculate the square root of the right side: 2.828427125

Break this problem into two subproblems by setting 
(y + -6) equal to 2.828427125 and -2.828427125.

Subproblem 1

y + -6 = 2.828427125 Simplifying y + -6 = 2.828427125 Reorder the terms: -6 + y = 2.828427125 Solving -6 + y = 2.828427125 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + y = 2.828427125 + 6 Combine like terms: -6 + 6 = 0 0 + y = 2.828427125 + 6 y = 2.828427125 + 6 Combine like terms: 2.828427125 + 6 = 8.828427125 y = 8.828427125 Simplifying y = 8.828427125

Subproblem 2

y + -6 = -2.828427125 Simplifying y + -6 = -2.828427125 Reorder the terms: -6 + y = -2.828427125 Solving -6 + y = -2.828427125 Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + y = -2.828427125 + 6 Combine like terms: -6 + 6 = 0 0 + y = -2.828427125 + 6 y = -2.828427125 + 6 Combine like terms: -2.828427125 + 6 = 3.171572875 y = 3.171572875 Simplifying y = 3.171572875

Solution

The solution to the problem is based on the solutions from the subproblems. y = {8.828427125, 3.171572875}

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